Integrand size = 28, antiderivative size = 229 \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=-\frac {231 e^3}{40 (b d-a e)^4 (d+e x)^{5/2}}-\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {77 b e^3}{8 (b d-a e)^5 (d+e x)^{3/2}}-\frac {231 b^2 e^3}{8 (b d-a e)^6 \sqrt {d+e x}}+\frac {231 b^{5/2} e^3 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{8 (b d-a e)^{13/2}} \]
[Out]
Time = 0.12 (sec) , antiderivative size = 229, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {27, 44, 53, 65, 214} \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {231 b^{5/2} e^3 \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{8 (b d-a e)^{13/2}}-\frac {231 b^2 e^3}{8 \sqrt {d+e x} (b d-a e)^6}-\frac {77 b e^3}{8 (d+e x)^{3/2} (b d-a e)^5}-\frac {231 e^3}{40 (d+e x)^{5/2} (b d-a e)^4}-\frac {33 e^2}{8 (a+b x) (d+e x)^{5/2} (b d-a e)^3}+\frac {11 e}{12 (a+b x)^2 (d+e x)^{5/2} (b d-a e)^2}-\frac {1}{3 (a+b x)^3 (d+e x)^{5/2} (b d-a e)} \]
[In]
[Out]
Rule 27
Rule 44
Rule 53
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{(a+b x)^4 (d+e x)^{7/2}} \, dx \\ & = -\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}-\frac {(11 e) \int \frac {1}{(a+b x)^3 (d+e x)^{7/2}} \, dx}{6 (b d-a e)} \\ & = -\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}+\frac {\left (33 e^2\right ) \int \frac {1}{(a+b x)^2 (d+e x)^{7/2}} \, dx}{8 (b d-a e)^2} \\ & = -\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {\left (231 e^3\right ) \int \frac {1}{(a+b x) (d+e x)^{7/2}} \, dx}{16 (b d-a e)^3} \\ & = -\frac {231 e^3}{40 (b d-a e)^4 (d+e x)^{5/2}}-\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {\left (231 b e^3\right ) \int \frac {1}{(a+b x) (d+e x)^{5/2}} \, dx}{16 (b d-a e)^4} \\ & = -\frac {231 e^3}{40 (b d-a e)^4 (d+e x)^{5/2}}-\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {77 b e^3}{8 (b d-a e)^5 (d+e x)^{3/2}}-\frac {\left (231 b^2 e^3\right ) \int \frac {1}{(a+b x) (d+e x)^{3/2}} \, dx}{16 (b d-a e)^5} \\ & = -\frac {231 e^3}{40 (b d-a e)^4 (d+e x)^{5/2}}-\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {77 b e^3}{8 (b d-a e)^5 (d+e x)^{3/2}}-\frac {231 b^2 e^3}{8 (b d-a e)^6 \sqrt {d+e x}}-\frac {\left (231 b^3 e^3\right ) \int \frac {1}{(a+b x) \sqrt {d+e x}} \, dx}{16 (b d-a e)^6} \\ & = -\frac {231 e^3}{40 (b d-a e)^4 (d+e x)^{5/2}}-\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {77 b e^3}{8 (b d-a e)^5 (d+e x)^{3/2}}-\frac {231 b^2 e^3}{8 (b d-a e)^6 \sqrt {d+e x}}-\frac {\left (231 b^3 e^2\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b d}{e}+\frac {b x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{8 (b d-a e)^6} \\ & = -\frac {231 e^3}{40 (b d-a e)^4 (d+e x)^{5/2}}-\frac {1}{3 (b d-a e) (a+b x)^3 (d+e x)^{5/2}}+\frac {11 e}{12 (b d-a e)^2 (a+b x)^2 (d+e x)^{5/2}}-\frac {33 e^2}{8 (b d-a e)^3 (a+b x) (d+e x)^{5/2}}-\frac {77 b e^3}{8 (b d-a e)^5 (d+e x)^{3/2}}-\frac {231 b^2 e^3}{8 (b d-a e)^6 \sqrt {d+e x}}+\frac {231 b^{5/2} e^3 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{8 (b d-a e)^{13/2}} \\ \end{align*}
Time = 1.05 (sec) , antiderivative size = 285, normalized size of antiderivative = 1.24 \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {-48 a^5 e^5+16 a^4 b e^4 (26 d+11 e x)-16 a^3 b^2 e^3 \left (173 d^2+242 d e x+99 e^2 x^2\right )-3 a^2 b^3 e^2 \left (445 d^3+4103 d^2 e x+6039 d e^2 x^2+2541 e^3 x^3\right )-2 a b^4 e \left (-155 d^4+715 d^3 e x+7227 d^2 e^2 x^2+10857 d e^3 x^3+4620 e^4 x^4\right )-b^5 \left (40 d^5-110 d^4 e x+495 d^3 e^2 x^2+5313 d^2 e^3 x^3+8085 d e^4 x^4+3465 e^5 x^5\right )}{120 (b d-a e)^6 (a+b x)^3 (d+e x)^{5/2}}-\frac {231 b^{5/2} e^3 \arctan \left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {-b d+a e}}\right )}{8 (-b d+a e)^{13/2}} \]
[In]
[Out]
Time = 2.52 (sec) , antiderivative size = 200, normalized size of antiderivative = 0.87
method | result | size |
derivativedivides | \(2 e^{3} \left (-\frac {b^{3} \left (\frac {\frac {71 b^{2} \left (e x +d \right )^{\frac {5}{2}}}{16}+\frac {59 \left (a e -b d \right ) b \left (e x +d \right )^{\frac {3}{2}}}{6}+\left (\frac {89}{16} a^{2} e^{2}-\frac {89}{8} a b d e +\frac {89}{16} b^{2} d^{2}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{3}}+\frac {231 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{16 \sqrt {\left (a e -b d \right ) b}}\right )}{\left (a e -b d \right )^{6}}-\frac {1}{5 \left (a e -b d \right )^{4} \left (e x +d \right )^{\frac {5}{2}}}-\frac {10 b^{2}}{\left (a e -b d \right )^{6} \sqrt {e x +d}}+\frac {4 b}{3 \left (a e -b d \right )^{5} \left (e x +d \right )^{\frac {3}{2}}}\right )\) | \(200\) |
default | \(2 e^{3} \left (-\frac {b^{3} \left (\frac {\frac {71 b^{2} \left (e x +d \right )^{\frac {5}{2}}}{16}+\frac {59 \left (a e -b d \right ) b \left (e x +d \right )^{\frac {3}{2}}}{6}+\left (\frac {89}{16} a^{2} e^{2}-\frac {89}{8} a b d e +\frac {89}{16} b^{2} d^{2}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{3}}+\frac {231 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{16 \sqrt {\left (a e -b d \right ) b}}\right )}{\left (a e -b d \right )^{6}}-\frac {1}{5 \left (a e -b d \right )^{4} \left (e x +d \right )^{\frac {5}{2}}}-\frac {10 b^{2}}{\left (a e -b d \right )^{6} \sqrt {e x +d}}+\frac {4 b}{3 \left (a e -b d \right )^{5} \left (e x +d \right )^{\frac {3}{2}}}\right )\) | \(200\) |
pseudoelliptic | \(-\frac {2 \left (\frac {1155 b^{3} e^{3} \left (e x +d \right )^{\frac {5}{2}} \left (b x +a \right )^{3} \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{16}+\left (\left (\frac {1155}{16} e^{5} x^{5}-\frac {55}{24} d^{4} e x +\frac {2695}{16} x^{4} d \,e^{4}+\frac {5}{6} d^{5}+\frac {1771}{16} d^{2} e^{3} x^{3}+\frac {165}{16} d^{3} e^{2} x^{2}\right ) b^{5}-\frac {155 \left (-\frac {924}{31} e^{4} x^{4}-\frac {10857}{155} d \,e^{3} x^{3}-\frac {7227}{155} d^{2} e^{2} x^{2}-\frac {143}{31} d^{3} e x +d^{4}\right ) e a \,b^{4}}{24}+\frac {445 \left (\frac {2541}{445} e^{3} x^{3}+\frac {6039}{445} d \,e^{2} x^{2}+\frac {4103}{445} d^{2} e x +d^{3}\right ) e^{2} a^{2} b^{3}}{16}+\frac {173 \left (\frac {99}{173} x^{2} e^{2}+\frac {242}{173} d e x +d^{2}\right ) e^{3} a^{3} b^{2}}{3}-\frac {26 \left (\frac {11 e x}{26}+d \right ) e^{4} a^{4} b}{3}+a^{5} e^{5}\right ) \sqrt {\left (a e -b d \right ) b}\right )}{5 \left (e x +d \right )^{\frac {5}{2}} \sqrt {\left (a e -b d \right ) b}\, \left (b x +a \right )^{3} \left (a e -b d \right )^{6}}\) | \(289\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 1270 vs. \(2 (193) = 386\).
Time = 1.03 (sec) , antiderivative size = 2550, normalized size of antiderivative = 11.14 \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\text {Too large to display} \]
[In]
[Out]
Timed out. \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\text {Timed out} \]
[In]
[Out]
Exception generated. \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\text {Exception raised: ValueError} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 480 vs. \(2 (193) = 386\).
Time = 0.28 (sec) , antiderivative size = 480, normalized size of antiderivative = 2.10 \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=-\frac {231 \, b^{3} e^{3} \arctan \left (\frac {\sqrt {e x + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{8 \, {\left (b^{6} d^{6} - 6 \, a b^{5} d^{5} e + 15 \, a^{2} b^{4} d^{4} e^{2} - 20 \, a^{3} b^{3} d^{3} e^{3} + 15 \, a^{4} b^{2} d^{2} e^{4} - 6 \, a^{5} b d e^{5} + a^{6} e^{6}\right )} \sqrt {-b^{2} d + a b e}} - \frac {2 \, {\left (150 \, {\left (e x + d\right )}^{2} b^{2} e^{3} + 20 \, {\left (e x + d\right )} b^{2} d e^{3} + 3 \, b^{2} d^{2} e^{3} - 20 \, {\left (e x + d\right )} a b e^{4} - 6 \, a b d e^{4} + 3 \, a^{2} e^{5}\right )}}{15 \, {\left (b^{6} d^{6} - 6 \, a b^{5} d^{5} e + 15 \, a^{2} b^{4} d^{4} e^{2} - 20 \, a^{3} b^{3} d^{3} e^{3} + 15 \, a^{4} b^{2} d^{2} e^{4} - 6 \, a^{5} b d e^{5} + a^{6} e^{6}\right )} {\left (e x + d\right )}^{\frac {5}{2}}} - \frac {213 \, {\left (e x + d\right )}^{\frac {5}{2}} b^{5} e^{3} - 472 \, {\left (e x + d\right )}^{\frac {3}{2}} b^{5} d e^{3} + 267 \, \sqrt {e x + d} b^{5} d^{2} e^{3} + 472 \, {\left (e x + d\right )}^{\frac {3}{2}} a b^{4} e^{4} - 534 \, \sqrt {e x + d} a b^{4} d e^{4} + 267 \, \sqrt {e x + d} a^{2} b^{3} e^{5}}{24 \, {\left (b^{6} d^{6} - 6 \, a b^{5} d^{5} e + 15 \, a^{2} b^{4} d^{4} e^{2} - 20 \, a^{3} b^{3} d^{3} e^{3} + 15 \, a^{4} b^{2} d^{2} e^{4} - 6 \, a^{5} b d e^{5} + a^{6} e^{6}\right )} {\left ({\left (e x + d\right )} b - b d + a e\right )}^{3}} \]
[In]
[Out]
Time = 9.83 (sec) , antiderivative size = 373, normalized size of antiderivative = 1.63 \[ \int \frac {1}{(d+e x)^{7/2} \left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=-\frac {\frac {2\,e^3}{5\,\left (a\,e-b\,d\right )}+\frac {66\,b^2\,e^3\,{\left (d+e\,x\right )}^2}{5\,{\left (a\,e-b\,d\right )}^3}+\frac {2541\,b^3\,e^3\,{\left (d+e\,x\right )}^3}{40\,{\left (a\,e-b\,d\right )}^4}+\frac {77\,b^4\,e^3\,{\left (d+e\,x\right )}^4}{{\left (a\,e-b\,d\right )}^5}+\frac {231\,b^5\,e^3\,{\left (d+e\,x\right )}^5}{8\,{\left (a\,e-b\,d\right )}^6}-\frac {22\,b\,e^3\,\left (d+e\,x\right )}{15\,{\left (a\,e-b\,d\right )}^2}}{{\left (d+e\,x\right )}^{5/2}\,\left (a^3\,e^3-3\,a^2\,b\,d\,e^2+3\,a\,b^2\,d^2\,e-b^3\,d^3\right )+b^3\,{\left (d+e\,x\right )}^{11/2}-\left (3\,b^3\,d-3\,a\,b^2\,e\right )\,{\left (d+e\,x\right )}^{9/2}+{\left (d+e\,x\right )}^{7/2}\,\left (3\,a^2\,b\,e^2-6\,a\,b^2\,d\,e+3\,b^3\,d^2\right )}-\frac {231\,b^{5/2}\,e^3\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {d+e\,x}\,\left (a^6\,e^6-6\,a^5\,b\,d\,e^5+15\,a^4\,b^2\,d^2\,e^4-20\,a^3\,b^3\,d^3\,e^3+15\,a^2\,b^4\,d^4\,e^2-6\,a\,b^5\,d^5\,e+b^6\,d^6\right )}{{\left (a\,e-b\,d\right )}^{13/2}}\right )}{8\,{\left (a\,e-b\,d\right )}^{13/2}} \]
[In]
[Out]